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βœ…Pascal Triangle

Using ^nC_r

Code
int nCr(int n, int r) {
    if(n == 0 || r == 0 || n == r)
        return 1;

    r = min(r, n - r);

    int res = 1;
    for(int i = 1; i <= r; i++) 
        res = res * (n - i + 1) / i;
    
    return res;
}
vector<vector<int> > Solution::solve(int A) {
    vector<vector<int>> res;
    for(int i = 0; i < A; i++) {
        res.push_back(vector<int>(i + 1));
        for(int j = 0; j <= i; j++)
            res[i][j] = nCr(i, j);
    }

    return res;
}

Time Complexity: O(n3)O(n^3)​

Space Complexity: O(n2)O(n^2)​ for the result

Very interesting article on pascal's trignale

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